iotcat 4 years ago
parent dca4d28d04
commit cbdd4fd36c
  1. 23
      source/_posts/electromagnetism.md

@ -45,22 +45,24 @@ Maxwell Dafa is good! !
{% raw %}<span class=".zh">{% endraw %} {% raw %}<span class=".zh">{% endraw %}
### 先供上麦克斯韦方程 膜拜膜拜( o=^•ェ•)o ### 先供上麦克斯韦方程 膜拜膜拜( o=^•ェ•)o
{% raw %} {% raw %}
<div style="overflow:scroll;"> <div style="overflow:scroll;">
{% endraw %} {% endraw %}
$$ $$
\nabla\cdot\vec{E} &=& \frac{\rho}{\varepsilon_0} \nabla\cdot\vec{E} = \frac{\rho}{\varepsilon_0}
$$ $$
$$ $$
\nabla\cdot\vec{B} &=& 0 \nabla\cdot\vec{B} = 0
$$ $$
$$ $$
\nabla\times\vec{E} &=& -\frac{\partial B}{\partial t} \nabla\times\vec{E} = -\frac{\partial B}{\partial t}
$$ $$
$$ $$
\nabla\times\vec{B} &=& \mu_0\left(\vec{J}+\varepsilon_0\frac{\partial E}{\partial t} \right) \nabla\times\vec{B} = \mu_0\left(\vec{J}+\varepsilon_0\frac{\partial E}{\partial t} \right)
$$ $$
@ -141,16 +143,19 @@ To Be Continued...
{% endraw %} {% endraw %}
$$ $$
\nabla\cdot\vec{E} &=& \frac{\rho}{\varepsilon_0} \nabla\cdot\vec{E} = \frac{\rho}{\varepsilon_0}
$$ $$
$$ $$
\nabla\cdot\vec{B} &=& 0 \nabla\cdot\vec{B} = 0
$$ $$
$$ $$
\nabla\times\vec{E} &=& -\frac{\partial B}{\partial t} \nabla\times\vec{E} = -\frac{\partial B}{\partial t}
$$ $$
$$ $$
\nabla\times\vec{B} &=& \mu_0\left(\vec{J}+\varepsilon_0\frac{\partial E}{\partial t} \right) \nabla\times\vec{B} = \mu_0\left(\vec{J}+\varepsilon_0\frac{\partial E}{\partial t} \right)
$$ $$

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